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x^2-x+1.92/12=0
We add all the numbers together, and all the variables
x^2-1x+1.92/12=0
We multiply all the terms by the denominator
x^2*12-1x*12+1.92=0
Wy multiply elements
12x^2-12x+1.92=0
a = 12; b = -12; c = +1.92;
Δ = b2-4ac
Δ = -122-4·12·1.92
Δ = 51.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-\sqrt{51.84}}{2*12}=\frac{12-\sqrt{51.84}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+\sqrt{51.84}}{2*12}=\frac{12+\sqrt{51.84}}{24} $
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